esse erro é pq não tem tabela de killers
no sql
abre sqlitestudio
vai no open sql query editor adiciona isso
CREATE TABLE killers ( id INTEGER PRIMARY KEY, death_id INTEGER NOT NULL, final_hit BOOLEAN NOT NULL DEFAULT FALSE, unjustified BOOLEAN NOT NULL DEFAULT FALSE, FOREIGN KEY ( death_id ) REFERENCES player_deaths ( id ) );
dps aperta F9




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Grupo: Campones
Registrado: 20/01/12
Posts: 15
Reputação: 0
Char no Tibia: pally
topfrags.lua
function onSay(cid, words, param) local max = 20 local letters_to_next = 20 local name_now local name = "Top Frags\n" local rkn = 0 name = name.."\n" name = name.."Rank Frags - Nome do Jogador\n" local v = db.getResult("SELECT `p`.`name` AS `name`, COUNT(`p`.`name`) as `frags` FROM `killers` k LEFT JOIN `player_killers` pk ON `k`.`id` = `pk`.`kill_id` LEFT JOIN `players` p ON `pk`.`player_id` = `p`.`id` WHERE `k`.`unjustified` = 1 GROUP BY `name` ORDER BY `frags` DESC;") repeat if v:getID() == -1 then break end rkn = rkn+1 name_now, l = v:getDataString("name"), string.len(v:getDataString("name")) name = name..rkn..". ["..v:getDataInt("frags").."] - "..name_now.." ".." ".."".."\n" until v:next() == false if name ~= "" then doShowTextDialog(cid,1903, name) end return TRUE endtentei usa da esse erro no console
OTSYS_SQLITE3_PREPARE(): SQLITE ERROR: no such table: killers (SELECT "p"."name" AS "name", COUNT("p"."name") as "frags" FROM "killers" k LEFT JOIN "player_killers" pk ON "k"."id" = "pk"."kill_id" LEFT JOIN "players" p ON "pk"."player_id" = "p"."id" WHERE "k"."unjustified" = 1 GROUP BY "name" ORDER BY "frags" DESC;)se não tiver jeito pra pega no 8.40 qual versão pega?
vlw galera do XTIBIA